Given the right triangle ABC
C = 90°
c = hyppotenusse
A=80°
a=18
B= 180-80-90 = 10°
Using the law of sines
[tex]\frac{a}{Sin(A)}=\frac{b}{Sin(B)}=\frac{c}{Sin(C)}[/tex][tex]\frac{18}{Sin(80)}=\frac{b}{Sin(10)}=\frac{c}{Sin(90)}[/tex]
Solving for b
[tex]\frac{18}{sin(80)}=\frac{b}{sin(10)}[/tex][tex]sin\left(10\right)*\frac{18}{sin(80)}=b[/tex][tex]b=3.174[/tex]
Solving for c
[tex]\frac{18}{s\imaginaryI n(80)}=\frac{c}{s\imaginaryI n(90)}[/tex][tex]s\mathrm{i}n(90)*\frac{18}{s\imaginaryI n(80)}=c[/tex][tex]c=18.278[/tex]
