what is the volume of the cone with a diameter of 2.8in and an aproximate height of 3in?

The volume of a cone is:
[tex]V=\frac{1}{3}\times h\times\pi\times r^2[/tex]Then, We have:
[tex]V=\frac{1}{3}\times\pi\times3in\times(\frac{2.8}{2}in)^2[/tex]The volume of the cone is:
[tex]V\approx6.1575\text{ }in^3\approx6in^3[/tex]