Given data:
The expression for the parabola is y=-x^2 +6x-5.
The given equation can be written as,
[tex]\begin{gathered} y=-x^2+6x-5 \\ =-(x^2-6x+5) \\ =-(x^2-2(3)(x)+9-4) \\ =-(x-3)^2+4 \end{gathered}[/tex]
Thus, the vertex of the parabola is (3,4).
