1. ** f(x) = -2x + 3. The function g(x) is perpendicular to f(x) and g(2) = 3. Which of the following equations could represent g(x)? (A) y = x-2 (B) y=-3x+4 (C) -x + 2y = 4 (D) 2x + 2y = 4

-x + 2y = 4
Explanations:The given function is:
f(x) = -2x + 3
The equation of a line is of the form:
y = mx + c
comparing this equation to f(x) = -2x + 3
m = -2
c = 3
When two lines are perpendicular to each other, the slope of one is the negative inverse of the other.
Since g(x) is perpendicular to f(x), it will have a slope, m = 1/2
Also, g(2) = 3
This means that, the line g(x) passes through the point (2, 3)
The point slope form of the equation of a line is:
y - y₁ = m(x - x₁)
Substituting m = 1/2 , x₁ = 2, and y₁ = 3 into the equation above:
[tex]\begin{gathered} y\text{ - 3 = }\frac{1}{2}(x\text{ - 2)} \\ y\text{ -3 = }\frac{1}{2}x\text{ - }1 \\ y\text{ = }\frac{1}{2}x\text{ - 1 + 3} \end{gathered}[/tex][tex]y\text{ = }\frac{1}{2}x\text{ + 2}[/tex]Multiply through by 2
2y = x + 4
-x + 2y = 4