can you explain how to do no.3 c??Solve only Question 3(iii)

Answer:
x = 3
Explanation:
Given:
[tex]x^2-6x+9=0[/tex]To find:
The value of x
To solve the given equation, we have to split the middle term using two factors of 9 whose sum is -6 and these factors are -3 and -3;
[tex]\begin{gathered} x^2-3x-3x+9=0 \\ x(x-3)-3(x-3)=0 \\ (x-3)(x-3)=0 \end{gathered}[/tex]Let's go ahead and solve for x;
[tex]\begin{gathered} x-3=0 \\ x=3 \end{gathered}[/tex]So the solution of the equation is x = 3