SOLUTION:
We are to find the equation of the line that goes through (-3,-1) and (3,3)
[tex]\begin{gathered} \frac{y-y_1}{x-x_1}\text{ = }\frac{y_2-y_1}{x_2-x_1} \\ \\ x_1=-3,x_2=3,y_1=-1andy_2=3_{} \\ \\ \frac{y-(-1)_{}}{x-(-3)_{}}\text{ = }\frac{3_{}-(-1)_{}}{3_{}-(-3)_{}} \\ \\ \frac{y\text{ + 1}}{x\text{ + 3}}\text{ = }\frac{3\text{ + 1}}{3\text{ + 3}} \\ \\ \frac{y\text{ + 1}}{x\text{ + 3}}\text{ = }\frac{4}{6} \\ \\ \frac{y\text{ + 1}}{x\text{ + 3}}\text{ = }\frac{2}{3} \end{gathered}[/tex][tex]\begin{gathered} 3\text{ ( y + 1 ) = 2 ( x + 3 )} \\ 3y\text{ + 3 = 2x + 6} \\ 3y\text{ -2x = 6 - 3} \\ 3y\text{ - 2x = 3} \\ \end{gathered}[/tex]
