The zeros are 3, -3 , 1/2
EXPLANATION
To find the zeros of the polynomial y = (x-3)(x+3)(2x-1)
Equate each factor to zero and solve for x.
x - 3 = 0
Add 3 to both-side of the equation.
x - 3 + 3 = 0 + 3
x = 3
x + 3 = 0
Subtract 3 from both-side of the equation.
x + 3 - 3 = 0 -3
x = -3
2x - 1 = 0
Add 1 to both-side of the equation.
2x = 1
Divide both-side of the equation by 2
x = 1/2
