Answer:
[tex]7.98\text{ L}[/tex]
Explanation:
Here, we want to get the new volume of the gas without changing the pressure
From Charles' law, we know that temperature and volume are directly proportional
We have that as:
[tex]\frac{V_1}{T_1}\text{ = }\frac{V_2}{T_2}[/tex]
From the question, we have the given values (we have to convert the given temperature values to Kelvin by adding 273.15 K) as:
V1 is 7.6 L
V2 = ?
T1 is 8 + 273.15 = 281.15 K
T2 is 22 + 273.15 = 295.15 K
Substituting the values, we have that as follows:
[tex]\begin{gathered} \frac{7.6}{281.15}\text{ = }\frac{V_2}{295.15} \\ \\ V_2\text{ = }\frac{7.6\times295.15}{281.15}\text{ = 7.98 l} \end{gathered}[/tex]
