Consider the function.f(x) = x2 − 1, x ≥ 1PART D ONLY

Given
[tex]\sqrt{x^2-1}[/tex]Find
domain and range of function and its inverse
Explanation
Domain =
[tex]x\leq-1\text{ or x}\ge1[/tex]Range=
[tex]y\ge0[/tex]Domain of inverse = R
Range =
[tex]y\ge1[/tex]Final Answer
Domain and range of inverse function
[tex]\begin{gathered} R \\ y\ge1 \end{gathered}[/tex]Domain and range of function
[tex]\begin{gathered} x\leq-1\text{ or x}\ge1 \\ y\ge0 \end{gathered}[/tex]