The given quadratic equation is
x^2 + 8x + 3 = 0
The general form of a quadratic equation is expressed as
ax^2 + bx + c = 0
By comparing both equations,
a = 1
b = 8
c = 3
We would solve it by applying the formula for quadratic equations which is expressed as
[tex]\begin{gathered} x\text{ = }\frac{-\text{ b}\pm\sqrt{b^2-4ac}}{2a} \\ Substitute\text{ the values. We have} \\ x\text{ = }\frac{-\text{ 8 }\pm\sqrt{8^2-4(1\times3)}}{2\times1} \\ x\text{ = }\frac{-\text{ 8}\pm\sqrt{64\text{ - 12}}}{2} \\ x\text{ = }\frac{-\text{ 8 }\pm\sqrt{52}}{2} \\ x\text{ = }\frac{-\text{ 8}}{2}\pm\frac{\sqrt{52}}{2} \end{gathered}[/tex]√52 can be written as 2√13
Thus,
x = - 4 ± 2√13/2
x = - 4 ± √13
