In this question, we have a situation in which we have to use the Calorimetry formula, which is how much heat was released or absorbed (in Joules), after we had a change in temperature of a compound. The formula for this Calorimetry question is:
Q = mcΔT
Where:
Q = is energy as Heat, 60.0 J
m = mass in grams, 10 grams
c = is the specific heat capacity, 1.87 J/g°C
ΔT = the change in temperature, calculated as Final Temperature - Initial T
Now we add these values into the formula:
60 = 10 * 1.87 * ΔT
60 = 18.7ΔT
ΔT = 60/18.7
ΔT = 3.2°C
The temperature had a 3.2°C of increase
