The given prism has two triangular surface and 3 rectangular prism.
The are of the triangular surface can be determined as,
[tex]\begin{gathered} \Delta=\frac{1}{2}\times14\text{ in}\times24\text{ in} \\ =168in^2 \end{gathered}[/tex]
The area of the base can be determined as,
[tex]\begin{gathered} A_b=14\text{ in}\times32\text{ in} \\ A_b=448in^2. \end{gathered}[/tex]
The area of the side rectangles can be determined as,
[tex]\begin{gathered} A_s=32\text{ in}\times25\text{ in} \\ =800in^2 \end{gathered}[/tex]
The total surface area can be determined as,
[tex]\begin{gathered} A=2\times\Delta+2\times A_s+A_b \\ =2\times168in^2+2\times800in^2+448in^2 \\ =2384in^2. \end{gathered}[/tex]
Thus, option (C) is the correct solution.
