The pressure of a submerged object in a fluid is given by:
[tex]P=\rho gh+P_{atm}[/tex]where ρ is the density of the fluis, g is the acceleration of gravity, h is the depth of the object and Patm is the pressure of the atmosphere. In this case we know that:
• The density of water is 1000 kg/m^3
,• The acceleration of gravity is 9.8 m/s^2
,• The depth of the object is 3 km, that is, 3000 m.
,• The atmospheric pressure is 101325 pascals.
Plugging these values in the equation given above we have:
[tex]\begin{gathered} P=(1000)(9.8)(3000)+101325 \\ P=2.95\times10^7 \end{gathered}[/tex]Therefore, the pressure at this depth is 2.95x10^7 Pa.
