SOLUTION:
If a marble is chosen at random and we are told the marble is red what is the probability that has the number 2 on it;
We have only one red marble out of eight red marbles that have number two on it.
[tex]P\text{ (2/red) = }\frac{1}{8}\text{ = 0.125 (3 d.p)}[/tex](b) If the first marble is replaced, and another marble is chosen at random if we are told that the marble has number 1 on it, what is the probability that the marble is red;
We have two marbles having 1 (i.e one blue and one red)
[tex]P(\text{red/1) = }\frac{1}{2}\text{ = 0.5 or 0.500 (3 d.p)}[/tex]r
