we have
[tex](2\sqrt{2)}(8\sqrt{18})[/tex]Remember that
18=2(3^2)
substitute
[tex]\begin{gathered} (2\sqrt{2)}(8\sqrt{2(3^2)}) \\ (2\sqrt{2)}(8\cdot3\sqrt{2}) \\ (2\sqrt{2)}(24\sqrt{2}) \\ (24\cdot2)(2) \\ 96 \end{gathered}[/tex]96 is a rational number, because
96=96/1
can be written as the quotient of two integers