Given
[tex]f\mleft(x\mright)=5x^2+3x-1[/tex]To find: The value of f(4).
Explanation:
It is given that,
[tex]f\mleft(x\mright)=5x^2+3x-1[/tex]That implies,
Put x=4.
Then,
[tex]\begin{gathered} f\mleft(4\mright)=5(4)^2+3(4)-1 \\ =5\times16+12-1 \\ =80+12-1 \\ =92-1 \\ =91 \end{gathered}[/tex]Hence, the value of f(4) is 91.
