#C
From the given figure we can see a rectangle with a semicircle cut from it
Then to find the area of the figure we will subtract the area of the semicircle from the area of the rectangle
Since the length of the rectangle is 6m
Since the width of the rectangle is 4 m
Since the rule of the area of the rectangle is
[tex]A=L\times W[/tex]Then substitute L by 6 and W by 4
[tex]\begin{gathered} A_R=6\times4 \\ A_R=24\text{ m}^2 \end{gathered}[/tex]Since the radius of the semicircle is 2 m
Since the rule of the area of the semicircle is
[tex]A=\frac{1}{2}\pi r^2[/tex]Then substitute r by 2
[tex]\begin{gathered} A_{semicircle}=\frac{1}{2}(\pi)(2^2) \\ A_{semicircle}=\frac{1}{2}(\pi)(4) \\ A_{semicircle}=2\pi \end{gathered}[/tex]Now, we will subtract the area of the semicircle from the area of the rectangle to find the area of the figure
[tex]\begin{gathered} A_F=A_R-A_{semicircle} \\ A_F=24-2\pi \\ A_F=(24-2\pi)\text{ m}^2 \end{gathered}[/tex]Then the exact area of the figure is (24 - 2pi) m^2
If the value of pi = 3.14, then
The area of the figure is
[tex]\begin{gathered} A_F=24-2(3.14) \\ A_F=17.72\text{ m}^2 \end{gathered}[/tex]The area of the figure is 17.72 m^2
