The equation of a line passing throughtwo points ( a,b) and (c,d) is given by:-
[tex]y-b=\frac{d-b}{c-a}(x-a)[/tex]
Now the given line passes through the points (-6,4) and (2,0) so the equation of the line will be:-
[tex]\begin{gathered} y-4-\frac{0-4}{2--(-6)}(x-(-6)) \\ y-4=\frac{-4}{2+6}(x+6) \\ y-4=\frac{-1}{2}(x+6) \end{gathered}[/tex]
So the correct answer is :-
[tex]y-4=\frac{-1}{2}(x+6)[/tex]
