Explanation
Part A
We are asked to find the starting height of the ball in its trajectory
To do so, let us first write the equation needed
[tex]h=-16t^2+110t+7[/tex]
Next, we will substitute t =0 into the equation
[tex]\begin{gathered} h=-16(0)^2+110(0)+7 \\ h=7 \end{gathered}[/tex]
Therefore the starting height will be 7
Part B
We are asked to obtain the original upward velocity of the ball
To do so, we will have to obtain the derivative
[tex]h^{\prime}(t)=-32t+110[/tex]
Next, we will substitute t =0
[tex]\begin{gathered} h^{\prime}(0)=-32(0)+110=110 \\ h^{\prime}(0)=110 \end{gathered}[/tex]
The original upward velocity is 110
