In order to estimate when the object hits the ground, let's use h(t) = 0 in the equation and calculate the value of t:
[tex]\begin{gathered} h(t)=841-16t^2 \\ 0=841-16t^2^{} \\ 16t^2=841 \\ t^2=\frac{841}{16} \\ t=\frac{29}{4}=7.25 \end{gathered}[/tex]Therefore the time for the object to hit the ground is 7.25 seconds.
Using Desmos to find the graphic solution, we have:
The graph has a y-value of zero for a horizontal value of 7.25, therefore h(7.25) = 0
(The quadrants II and III are not useful since time can't be negative).
