Given that the time to complete an exam is approximately normal with a mean 47 minutes and a standard deviation of 2 minutes.
Here
[tex]\begin{gathered} \mu=47 \\ \sigma=2 \end{gathered}[/tex]Therefore,
[tex]\begin{gathered} \mu-3\sigma=47-3(2) \\ =47-6 \\ =41 \\ \mu-2\sigma=47-2(2) \\ =47-4 \\ =43 \end{gathered}[/tex][tex]\begin{gathered} \mu-\sigma=47-2 \\ =45 \\ \mu=47 \\ \mu+\sigma=47+2 \\ =49 \\ \mu+2\sigma=47+2(2) \\ =47+4 \\ =51 \\ \mu+3\sigma=47+3(2) \\ =47+6 \\ =53 \end{gathered}[/tex]Hence, the values in the given blanks from the very left sides are
41, 43, 45, 47, 49, 51, 53