Answer:
Explanation:
Let us call
a = slope of line A
b = slope of line B
then the two lines are perpendicular if
[tex]a=-\frac{1}{b}[/tex]Now, what is the value of a, the slope of line A?
We find it by using the two points that lie on line A: (0, 3) and (3, 1).
The slope of line A is
[tex]\text{slope a}=\frac{\text{rise}}{\text{run}}=\frac{3-1}{0-3}=\frac{2}{-3}[/tex]Hence,
[tex]a=-\frac{2}{3}[/tex]Now what is the value of b, the slope of line B?
We find it using the two points that lie on B: (-1, 4) and (-7, 5).
[tex]\text{slope b=}\frac{rise}{\text{run}}=\frac{4-5}{-1-(-7)}[/tex][tex]=\frac{-1}{-1+7}=-\frac{1}{6}[/tex]Hence,
[tex]\text{slope b = -}\frac{1}{6}[/tex]Now is it true that a = -1 / b?
Let us see.
[tex]-\frac{1}{b}=-\frac{1}{-1/6}=6[/tex]which is not equal to - 2/3!
Since the condition a = -1/b is not met, the two lines are not perpendicular.
