contestada

Given the function k(x)=−lnx, which of the following functions has a graph identical to k(x)q(x)=lnxq(x)=ln(1x)q(x)=ln(−x)q(x)=3e−x−1

Respuesta :

according to the properties of logarithms

[tex]\begin{gathered} \ln (\frac{1}{x})=\ln (1)-\ln (x);\ln (1)=0 \\ \Rightarrow0-\ln (x) \\ \Rightarrow\ln (\frac{1}{x})=-\ln (x) \end{gathered}[/tex]

therefore, the answer is option 2

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