[tex]\begin{gathered} \text{ We have to find } \\ P(\text{Democrat}2020|\text{Democrat}1976) \\ \text{The conditional probability is the probability of the intersection divided} \\ by\text{ the total probability of Democrat 1976!} \\ \text{thus} \\ P=\frac{\frac{12}{51}}{\frac{12}{24}} \\ P=\frac{24}{51} \\ \\ P=0.4705 \\ \text{thus the frequence is } \end{gathered}[/tex]
Thus the frequency is 47.0%
