we are to solve
[tex]\frac{x\text{ + 3}}{x\text{ + 2}}\text{ }\times\text{ }\frac{x\text{ -3}}{x\text{ -2}}[/tex]simplifying this we get
[tex]\begin{gathered} \frac{x\text{ + 3}}{x\text{ + 2}}\text{ X }\frac{x\text{ -3}}{x\text{ -2}} \\ =\text{ }\frac{(x\text{ + 3)(x - 3)}}{(x\text{ + 2)(x - 2)}} \\ \exp anding\text{ the expression} \\ =\text{ }\frac{x^2\text{ -3x + 3x - 9}}{x^2-2x\text{ + 2x - 4}} \\ =\text{ }\frac{x^2\text{ - 9}}{x^2\text{ - 4}} \end{gathered}[/tex]Hence, the correct option is B
