Given:
Here we have a rectangle with 6*22 ft
we also have triangle which is exact fit as given in question.
Required:
We need to find the appropriate option.
Explanation:
We need to compare the areas of both
area of triangle
[tex]\begin{gathered} A_T=\frac{1}{2}bh \\ \\ A_T=\frac{1}{2}*22*6 \\ \\ A_T=66\text{ ft}^2 \end{gathered}[/tex]
now we to find the area of rectangle
[tex]A_R=bh=132\text{ ft}^2[/tex]
Final answer:
Clearly we can see that the area of triangle is 1/2 of area of rectangle
8)
here we can solve this problem with formulas only
compare both formula
[tex]\begin{gathered} A_R=hb \\ and \\ A_T=\frac{1}{2}hb \end{gathered}[/tex]
by this also
triangle's is 1/2 times the rectangle's area
