Given data
*The given angle is
[tex]\theta=45.0^0[/tex]
*The given initial velocity is u = 6.25 m/s
The formula for the horizontal range is given as
[tex]R=\frac{u^2\sin 2\theta}{g}[/tex]
*Here g is the acceleration due to gravity
Substitute the values in the above expression as
[tex]\begin{gathered} R=\frac{(6.25)^2\sin (2\times45.0^0)}{9.8} \\ =3.98\text{ m} \end{gathered}[/tex]
