An air traffic controller is tracking two planes. To start, Plane A was an altitude of 970 M, and Plane B was at an altitude of 1438 M. Plane A is losing altitude at 17 meters per second, and Plane B is losing altitude at 26 meters per second.Let x be tbe number of seconds that have passed.(a) For each plane, write an expression for the altitude of the plane after x seconds. Altitude of Plane A (in meters) = ?? Altitude of Plane B (in meters) = ??(b) Write an equation to show when the two planes would be at the same altitude.

Respuesta :

a)

The altitude equation modelling would take the form:

Initial Altitude - (Rate of decrease of Altitude)x

For Plane A

[tex]970-17x[/tex]

For Plane B

[tex]1438-26x[/tex]b)

To find the the time when two planes would be the same Altitude, we equate both expressions and find the value of x.

Shown below:

[tex]\begin{gathered} 970-17x=1438-26x \\ -17x+26x=1438-970 \\ 9x=468 \\ x=\frac{468}{9} \\ x=52 \end{gathered}[/tex]

Thus, we can say that the altitude of both planes would be the same after 52 seconds!

Answer: 52 seconds