In order to calculate the decibel level of the given sound, let's use the value of I = 2.8 * 10^7 in the given formula and solve the equation for D.
So we have:
[tex]\begin{gathered} D=10\cdot\log (10^{12}\cdot2.8\cdot10^7) \\ D=10\cdot\log (2.8\cdot10^{19}) \\ D=10\cdot(\log (2.8)+\log (10^{19})) \\ D=10\cdot(0.447+19\cdot\log (10)) \\ D=10\cdot(0.447+19) \\ D=10\cdot(19.447) \\ D=194.47 \end{gathered}[/tex]
Rounding to the nearest whole number, we have a decibel level of 194.47 dB.
Since it's greater than 160, it would cause a ruptured eardrum.
