Solution
The problem is under binomial distribution probability.
The formula to be used is shown below
Fot the question before us,
n = 6
x = 2
p = 1 - 95% = 1 - 0.95 = 0.05
q = 95% = 0.95
Sunstituting the values into the above formula, we have
[tex]\begin{gathered} p_2=^6C_2(0.05)^2(0.95)^{6-2} \\ p_2=^6C_2(0.05)^2(0.95)^{6-2} \\ p_2=15(0.0025)(0.81450625) \\ p_2=0.0305 \\ p_2=\frac{3.05}{100} \\ p_2=3.05\text{\%} \end{gathered}[/tex]The answer is 3.05%
