from the information given in the question we have the following
as given in the question
[tex]\begin{gathered} \angle\text{ ACB = 180}^{\circ} \\ \angle DCB=135^{\circ} \\ \end{gathered}[/tex]
We are to find angle DCA
Using the property of straight line
[tex]\begin{gathered} \angle ACB\text{ = }\angle DCA\text{ + }\angle\text{DCB }(Sum\text{ of angles on a straight line = 180)} \\ 180^{\circ}\text{ = }\angle DCA\text{ + }135^{\circ} \\ 180^{\circ}-135^{\circ}\text{ = }\angle DCA \\ \angle DCA=45^{\circ} \end{gathered}[/tex]
Therefore,
angle
