Respuesta :
1) Balance the chemical equation.
[tex]CaCO_{3(s)}\rightarrow CaO_{(s)}+CO_{2(g)}[/tex]2) List known values
ΔHf of CaCO3 = -1207.6 kJ/mol
ΔHf of CaO = -634.9 kJ/mol
ΔHf CO2 = -393.5 kJ/mol
3) Write the enthalpy change equation.
[tex]\Delta Hº=\Sigma n\Delta Hºf(products)-\Sigma n\Delta Hºf(reactants)[/tex]n= stoichiometric coefficients
4) Plug in the known values
[tex]\Delta Hº=\lbrack(1*CaO)+(1*CO_2)-(1*CaCO_3)\rbrack[/tex][tex]\Delta Hº=\lbrack(1*-635\text{ }kJ/mol)+(1*-393.5\text{ }kJ/mol)-(1*-1207.6\text{ }kJ/mol)\rbrack[/tex][tex]\Delta Hº=+179.1\text{ }kJ/mol[/tex]
The
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