Given the following
[tex]\begin{gathered} M=0.549\text{ mol/L} \\ V=25.0mL=25\times10^{-3}L=0.025L \\ M=\text{Molarity} \\ V=\text{Volume} \end{gathered}[/tex]
To find the millimoles of Barium Chloride
To achieve, define molarity
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution
So,
[tex]M=\frac{mole}{Volume}[/tex]
Substitute the given into the formula above
[tex]\begin{gathered} 0.549\text{ mol/L=}\frac{mole}{0.025L} \\ \text{mole}=0.549\text{ mol/L}\times0.025L \\ \text{mole}=0.013725\text{mol} \\ \text{millimole}=\frac{0.013725}{1000} \\ \text{millimole}=0.000013725 \\ \text{millimole}=0.0000137(\text{nearest 3 significant digits)} \end{gathered}[/tex]
Hence, the millimoles of Barium Chloride correct to 3 significant digits is 0.0000137 millimoles
