Given
A training field is formed by joining a rectangle and two semi-circles.
The dimensions of the rectangle is 80m and 68m.
To find: The area of the training field.
Explanation:
It is given that,
The length of the rectangle is 80m.
The breadth of the rectangle is 68m.
Also, the radius of the semicircle is,
[tex]\begin{gathered} r=\frac{68}{2} \\ r=34m \end{gathered}[/tex]
Therefore, the area of the training field is,
[tex]\begin{gathered} Area\text{ }of\text{ }the\text{ }training\text{ }field=Area\text{ }of\text{ }rectangle+2\times Area\text{ }of\text{ semicircle} \\ =(80\times68)+2\times\frac{1}{2}\times\frac{22}{7}\times(34)^2 \\ =5440+3633.142857142 \\ =9073.142857142 \\ =9073.14m^2 \end{gathered}[/tex]
Hence, the area of the training field is 9073.14m^2.
