How many grams of solute would you use to prepare the following solutions?1.08 L of 0.438 M glucose (C6H12O6) Express your answer with the appropriate units.

Respuesta :

Answer

85.22 grams of glucose

Procedure

Data: 180.156 g/mol (glucose molecular weight)

To solve this question you will need to convert the glucose from moles to grams using the molecular weight, also considering the volume of the solution. This is done as follows;

[tex]1.08\text{ L solution}\frac{0.438\text{ moles glucose}}{1\text{ L solution}}\frac{180.156\text{ g glucose}}{1\text{ mol glucose}}=85.22\text{ grams of glucose}[/tex]