According to the given data we have the following:
equation of the line that passes through the point (-8, -12)
slope m=6
equation of the line is y=mx +b
Therefore, to find the equation in point-slope form and slope-intercept form would we would plug the point (-8, -12) and the slope 6 at the equation above, so:
-12=6(-8) + b
-12=-48 +b
b=-36
Therefore, y=6x -36
