We are given the following information
Mass of person = 66.5 kg
Mass of Earth = 5.97x10^24 kg
Radius of Earth = 6.38x10^6 m
The gravitation force experienced by the person is given by
[tex]F=G\frac{m_{}\cdot M}{r^2}[/tex]Where m is the mass of the person, M is the mass of Earth, r is the radius of Earth and G is the gravitational constant.
G = 6.67430×10⁻¹¹ m³/kg⋅s²
Let us substitute the given values into the above formula
[tex]F=G\frac{m_{}\cdot M}{r^2}=6.67430\times10^{-11}\frac{66.5\cdot5.97\times10^{24}}{(6.38\times10^6)^2}=651\; N[/tex]Therefore, the magnitude of the gravitation force is 651 N
