Visualizing the given, we have
[tex]\begin{gathered} \text{We can solve this using tangent function} \\ \\ \tan 11.3\degree=\frac{BC}{AC} \end{gathered}[/tex]Find BC
Convert Tamara's height into feet first
62 inches → 31/6 feet
BC = 15 feet - 31/6 feet
BC = 59/6 feet
Now that we have BC, we can solve for AC (which is the distance from the flagpole to where Tamara is standing.
[tex]\begin{gathered} \tan 11.3\degree=\frac{BC}{AC} \\ AC=\frac{BC}{\tan 11.3\degree} \\ AC=\frac{\frac{59}{6}\text{ feet}}{\tan 11.3\degree} \\ AC=49.21102605\text{ feet} \end{gathered}[/tex]Rounding off to the nearest 2 decimal place.
The flagpole is 49.21 feet to where Tamara is standing.