Respuesta :

[tex]\begin{gathered} A)\text{ 3(n - 6) = 3n -18} \\ B)\text{ 3(6-n)=-3n+18} \\ C)6(n-3)=6n-18 \\ D)6(3-n)=-6n+18 \\ Since\text{ n<0 then the greatest value is D} \end{gathered}[/tex]