ANSWER:
The probability is 68.63%
STEP-BY-STEP EXPLANATION:
The first thing is to look in the normal distribution table for the corresponding z values:
Replacing we have:
[tex]\begin{gathered} P\mleft(-0.640.64) \\ P(z<1.62)=0.9474 \\ P(z>0.64)=0.2611 \\ P(-0.64
