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The student removes the 16 wire from the circuit and cuts it into two equal lengths.He then connects the two lengths in parallel between K and L, as shown in Fig. 8.2.

The student removes the 16 wire from the circuit and cuts it into two equal lengthsHe then connects the two lengths in parallel between K and L as shown in Fig class=

Respuesta :

To find the equivalent resistance of a parallel resistors we use:

[tex]\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}[/tex]

In this case both resistor one and two have a 16 Ω resistance, plugging these in the equation above we have:

[tex]\begin{gathered} \frac{1}{R_{eq}}=\frac{1}{16}+\frac{1}{16} \\ \frac{1}{R_{eq}}=\frac{16+16}{256} \\ \frac{1}{R_{eq}}=\frac{32}{256} \\ \frac{1}{R_{eq}}=\frac{1}{8} \\ R_{eq}=8 \end{gathered}[/tex]

Therefore, the resistance of the two wires is 8 Ω