Given: A rhombus YWZA with XY=7 ft and XA=8 ft.
Since the diagonals of a rhombus bisect each other, therefore
[tex]\begin{gathered} YZ=2\times XY=2\times7=14\text{ ft} \\ AW=2\times XA=2\times8=16\text{ ft} \end{gathered}[/tex]
As YZ and AW are the diagonals of this rhombus, its area will be:
[tex]\text{Area of rhombus=}\frac{\text{Product of diagonals}}{2}=\frac{14\times16}{2}=112ft^2[/tex]
Thus, the area of this rhombus is 112 feet squared.
