No.
1) Because in the cubic root of 8, as below represented in this function:
[tex]\begin{gathered} f(x)\text{ =}\sqrt[3]{x} \\ f(8)\text{ =}\sqrt[3]{8}\text{ = 2} \\ f(-8)\text{ =}\sqrt[3]{-8\text{ }}\text{ =-2} \end{gathered}[/tex]There is no other negative number that can be inserted in the Domain to yield a positive value in the Range.
Unlike, the quadratic radical function. For example:
[tex]\begin{gathered} f(x)\text{ =}\sqrt{x} \\ f(25)\text{ =+5 or -5} \\ (-5)^2=25and(5)^2=25 \end{gathered}[/tex]