Given:
Triangle ABC is similar to triangle QRS
Using the concept of similarity of triangles:
Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion.
Hence, we can write:
[tex]\begin{gathered} \frac{6}{n}\text{ = }\frac{2}{5} \\ \text{Cross}-\text{Multiply} \\ n\text{ }\times\text{ 2 = 6 }\times5 \\ \text{Divide both sides by 2} \\ n\text{ = }\frac{6\times5}{2} \\ n\text{ = 15} \end{gathered}[/tex]
Answer:
n = 15
