Explanation
From the statement, we know that the speed of the cheetah is:
[tex]S=1.73\times\frac{km}{m\imaginaryI n}.[/tex]
We have the following ratios:
[tex]\begin{gathered} 1=\frac{60\text{ min}}{1\text{ h}}, \\ 1=\frac{1\text{ mi}}{1.61\text{ km}}. \end{gathered}[/tex]
1) To convert the speed from km/min to mi/h, we rewrite the expression using the first ratio:
[tex]S=1.73\times\frac{km}{m\imaginaryI n}\times1=1.73\times\frac{\text{km}}{\text{m}\mathrm{i}\text{n}}\times\frac{60\text{ min}}{1h}=1.73\times60\times\frac{km}{h}.[/tex]
2) Now, we use the second ratio:
[tex]S=1.73\times60\times\frac{km}{h}\times1=1.73\times60\times\frac{km}{h}\times\frac{1\text{ mi}}{1.61km}=\frac{1.73\times60}{1.61}\times\frac{mi}{h}.[/tex]
3) Finally, computing the product and quotient, we get:
[tex]S\cong64.5\frac{mi}{h}.[/tex]Answer
64.5 mi/h
