We are given that a cyclist covers a distance of 20 km in 30 minutes. To determine the average speed we will use the following formula:
[tex]v=\frac{d}{t}[/tex]Where:
[tex]\begin{gathered} d=\text{ distance} \\ t=\text{ time} \end{gathered}[/tex]Since we desire to obtain the speed in units of km/h we need to convert the 30 minutes into hours. To do that we will use the following conversion factor:
[tex]60\min =1h[/tex]Multiplying by the conversion factor we get:
[tex]30\min \times\frac{1h}{60\min }=0.5h[/tex]Now we substitute in the equation for speed:
[tex]v=\frac{20\operatorname{km}}{0.5h}[/tex]Now we solve the operations:
[tex]v=\frac{40\operatorname{km}}{h}[/tex]Part B. The average speed is 40 km/h. Since the average speed is the mean of the speed of the cyclist it is possible that a peak of 50 km/h could be reached.
