The distance of the Ship A after 2hours;
[tex]\begin{gathered} d=\text{speed }\times time \\ d=20\times2 \\ d=40m \end{gathered}[/tex]The distance of the Ship B after 2 hours;
[tex]\begin{gathered} d=28\times2 \\ d=56m \end{gathered}[/tex]Then, we have;
Then, using cosine rule, we have;
[tex]\begin{gathered} p^2=a^2+b^2-2ab\cos P \\ \text{Where a=56, b=40, P=100}^o \\ p^2=(56)^2+(40)^2-2(56)(40)\cos (100) \\ p^2=4736-(-777.94) \\ p^2=5513.94 \\ p=74.25 \\ p\approx74miles \end{gathered}[/tex]The distance between the two ships after 2 hours is 74miles.
