Given:
The height of the Statue of Liberty, h=93 m.
The angle of elevation of the bird on top of the statue as viewed by a camera on the ground, θ=30°.
The height of the camera lens with respect to the ground, y=1 m.
Let x be the horizontal distance from base of the statue to the camera.
Using trigonometric property in the above triangle,
[tex]\begin{gathered} \tan \theta=\frac{opposite\text{ side}}{adjacent\text{ side}} \\ \tan \theta=\frac{h-y}{x} \end{gathered}[/tex]Substitute the values and solve the equation for x.
[tex]\begin{gathered} \tan 30^{\circ}=\frac{93m-1m}{x} \\ x=\frac{92\text{ m}}{\tan 30^{\circ}} \\ =159.3\text{ m} \end{gathered}[/tex]Therefore, the horizontal distance from base of the statue to the camera is m.
