ANSWER
[tex]\begin{equation*} 4.67*10^{-9}\text{ }N \end{equation*}[/tex]EXPLANATION
Parameters given:
Mass of the student, M = 70 kg
Mass of the textbook, m = 1 kg
Distance, r = 1 m
To find the gravitational force acting between the student and the textbook, apply the formula for gravitational force:
[tex]F=\frac{GMm}{r^2}[/tex]where G = gravitational constant
Therefore, the gravitational force acting between the student and the textbook is:
[tex]\begin{gathered} F=\frac{6.67430*10^{-11}*70*1}{1^2} \\ \\ F=4.67*10^{-9}\text{ }N \end{gathered}[/tex]That is the answer.
