The general equation of the circle is :
[tex](x-h)^2+(y-k)^2=r^2[/tex]Where the center at the point ( h , k ) and the radius = r
It is required to find the equation of the circle with center at (-8 , 3) and r = 4
So,
h = -8
k = 3
r = 4
substitute with the previous value at the general equation of the circle
so,
[tex]\begin{gathered} (x-(-8))^2+(y-3)^2=4^2 \\ \\ (x+8)^2+(y-3)^2=16 \end{gathered}[/tex]